Geometry
posted by Debbie .
A right triangle and a square share a side. The hypotenuse of the triangle measures 10 cm. One base of the triangle measures 4 cm. Neither the known base nor the hypotenuse is the side that is shared with the square. Find the area of the square.

Given triangle ABC, the right angle being at B.
Given AC = 10
Given AB = 4
Neither AB nor AC share the side of the square.
Therefore, BC = the side of the square being BC = sqrt(10^2  4^2) = 9.1651 making the area of the square 84 sq.cm. 
I have a triangle with the base of 11 and all the sides look about the same but i don't know how to find out the height?
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