A truck speed increases uniformly from 10 m/s to 30 m/s in 20 seconds.

Find the ff:
a. average speed
b. acceleration
c. distance covered during the period

a. V=(V1 + V2) / 2=(10 + 30) / 2 = 20 mi/h.

b. a = (Vf - Vo) / t,
a = (30 - 10) / 20 = 1m/s^2.

c. d = (Vf^2 - Vo^2) / 2a,
d = (900 - 100) / 2 = 400m.

a trucks speed increase uniformly from 15 mi/h to 60 mi/h in 20 seconds.

determine: A. what is average speed
B. acceleration C. distance travelled

a. Why did the truck get invited to the party? Because it has the "average speed" dance moves! To find the average speed, we can use the formula: average speed = total distance / total time. In this case, the total distance covered by the truck is (30 + 10) / 2 = 20 m/s. The total time it took is 20 seconds. So the average speed is 20 m/s.

b. The truck's acceleration is pretty impressive, just like a clown learning to juggle! To find the acceleration, we can use the formula: acceleration = change in velocity / time. The change in velocity is 30 m/s - 10 m/s = 20 m/s, and the time is 20 seconds. So the acceleration is 20 m/s / 20 s = 1 m/s².

c. The distance covered during the period is like a clown squeezing into a tiny car, quite impressive! To find the distance, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time². The initial velocity is 10 m/s, and the time is 20 seconds. The acceleration is 1 m/s². Plugging in these values, we get distance = 10 m/s * 20 s + 0.5 * 1 m/s² * (20 s)² = 200 m + 0.5 m/s² * 400 s² = 200 m + 200 m = 400 m.

So, the distance covered during the period is 400 meters.

To find the average speed, you can use the formula:

Average Speed = Total Distance / Total Time

Given that the truck's speed increases uniformly from 10 m/s to 30 m/s in 20 seconds, the total distance covered will be the average of the initial and final speeds multiplied by the total time taken.

Let's calculate each part step-by-step:

a. Average Speed:
Average Speed = (Initial Speed + Final Speed) / 2

Average Speed = (10 m/s + 30 m/s) / 2 = 20 m/s

Therefore, the average speed is 20 m/s.

b. Acceleration:
Acceleration is the rate at which velocity changes per unit time. In this case, the acceleration will be:

Acceleration = Change in Velocity / Time

Change in Velocity = Final Velocity - Initial Velocity
Change in Velocity = 30 m/s - 10 m/s = 20 m/s

Acceleration = 20 m/s / 20 s = 1 m/s²

Therefore, the acceleration is 1 m/s².

c. Distance Covered During the Period:
Using the equation of motion:

Distance = (Initial Velocity + Final Velocity) × Time / 2

Distance = (10 m/s + 30 m/s) × 20 s / 2

Distance = 20 m/s × 20 s / 2 = 400 m

Therefore, the distance covered during the period is 400 meters.

To find the answers to these questions, we will use the kinematic equations of motion, specifically the equations of uniformly accelerated motion.

The given information is as follows:
Initial speed, u = 10 m/s
Final speed, v = 30 m/s
Time, t = 20 seconds

Now, let's find the answers step by step:

a. Average Speed:
Average speed is defined as the total distance traveled divided by the total time taken.

To find the distance traveled, we can use the formula:

Distance, s = (v - u) * t

Substituting the given values, we have:
s = (30 m/s - 10 m/s) * 20 seconds
s = 20 m/s * 20 seconds
s = 400 meters

Therefore, the distance covered during the period is 400 meters.

To find the average speed, we can use the formula:

Average speed = Total distance / Total time
Average speed = 400 meters / 20 seconds
Average speed = 20 m/s

Hence, the average speed is 20 m/s.

b. Acceleration:
Acceleration is the rate of change of velocity with respect to time.

To find the acceleration, we can use the formula:

Acceleration, a = (v - u) / t

Substituting the given values, we have:
a = (30 m/s - 10 m/s) / 20 seconds
a = 20 m/s / 20 seconds
a = 1 m/s^2

Thus, the acceleration is 1 m/s^2.

c. Distance Covered:
As already calculated above, the distance covered during the period is 400 meters.

Therefore, the distance covered during the period is 400 meters.

In summary:
a. Average Speed = 20 m/s
b. Acceleration = 1 m/s^2
c. Distance Covered = 400 meters