Tickets for the Universal Studios amusement park are priced at $32 for Senior Citizens,$66 for adults and $48 for children. There are 10 senior citizens in a tour group, the rest are adults and children. There were 2/3 as many adults as children. The total paid was $3632. How many children were there?

i need non algebra solutions pls

I apologize but the onnly way I can currently think of involves algebra if you would like to know it let me know. :)

please show me the method and i'll try to see how it goes, tks

To find the number of children, we'll follow these steps:

Step 1: Assign variables to the unknowns:
Let's assume the number of children in the tour group is "x".

Step 2: Set up equations based on the given information:
According to the second statement, there are 2/3 as many adults as children. So, the number of adults would be (2/3)x.

The number of senior citizens is given as 10.

Step 3: Use the equations to create an expression for the payment:
The total amount paid is $3632. To calculate this, we need to multiply the number of tickets for each category (senior citizens, adults, and children) by their respective ticket prices and sum them up:

Total payment = (Number of senior citizens × price per senior citizen ticket)
+ (Number of adults × price per adult ticket)
+ (Number of children × price per child ticket)

$3632 = (10 × $32) + ((2/3)x × $66) + (x × $48)

Step 4: Simplify and solve the equation:
$3632 = $320 + ((2/3)x × $66) + (x × $48)
$3632 = $320 + (2/3)x × $66 + x × $48

Step 5: Simplify further and solve the equation:
$3632 = $320 + (44/3)x + 48x

Now, we can multiply both sides of the equation by 3 to eliminate the fraction:

3 × ($3632) = 3 × ($320) + 3 × ((44/3)x) + 3 × (48x)
$10896 = $960 + 44x + 144x

Combine like terms:
$10896 = $960 + 188x

Subtract $960 from both sides:
$10896 - $960 = 188x
$9988 = 188x

Divide both sides by 188 to solve for x (the number of children):
$9988 ÷ 188 = x
53 = x

Therefore, there were 53 children in the tour group.