The attendance at a baseball game was 400 people. Student tickets cost $2 and adult tickets cost $3. Total ticket sales were $1050. How many tickets of each type were sold?

Let s = student tickets and a = adult tickets.

s + a = 400, so s = 400-a

2s + 3a = 1050

Substitute 400-a for s in second equation and solve for a. Insert that value into the first equation and solve for s. Check by inserting both values into the second equation.

AT A HIGH SCHOOL BASKETBALL GAME; 500 TICKET WERE SOLD. ADULT TICKETS COST $5.50 AND STUDENT TICKET COST $3.50 IF THE TOTAL AMOUNT COLLECTED WAS 2200. HOW MANY STUDENT TICKET WERE SOLD AND HOW MANY ADULT TICKET WERE SOLD

23

To solve this problem, we can set up a system of equations. Let's denote the number of student tickets as 's' and the number of adult tickets as 'a'.

From the given information, we can form two equations:

1. The total number of tickets sold is 400:
s + a = 400

2. The total ticket sales were $1050:
2s + 3a = 1050

Now we can solve this system of equations to find the values of 's' and 'a'.

To eliminate one variable, we can multiply the first equation by 2, then subtract it from the second equation:

2s + 3a - (2s + 2a) = 1050 - 2(400)

This simplifies to:

a = 1050 - 800
a = 250

Substituting this value of 'a' into the first equation, we find:

s + 250 = 400
s = 150

Therefore, 150 student tickets and 250 adult tickets were sold.