A baby sitter pushing a stroller starts from

rest and accelerates uniformly at a rate of
0.511 m/s
2
.
What is the velocity of the stroller after it
has traveled 5.38 m?
Answer in units of m/s

Vf^2=2ad solve for Vf

.511m/s

To find the velocity of the stroller after it has traveled a certain distance, you can use the equation of motion:

v^2 = u^2 + 2as

Where:
v is the final velocity
u is the initial velocity (which is 0 m/s since the stroller starts from rest)
a is the acceleration (0.511 m/s^2 in this case)
s is the distance traveled (5.38 m)

Since the initial velocity is 0 m/s, the equation simplifies to:

v^2 = 2as

You can rearrange the equation to solve for v:

v = √(2as)

Substituting the given values:

v = √(2 * 0.511 m/s^2 * 5.38 m)

Calculating this, we get:

v ≈ √(5.51 m^2/s^2)

Finally, taking the square root of 5.51 m^2/s^2, we find:

v ≈ 2.35 m/s

Therefore, the velocity of the stroller after it has traveled 5.38 m is approximately 2.35 m/s.