A number has more ones than tens. The value of the tens digit is 50. The ones digit in the number is less than 7. What are the possible numbers?
I'll be glad to check your answer.
56,55,54,53,52,51
To find the possible numbers that satisfy the given conditions, we can follow these steps:
Step 1: Determine the range of possible values for the ones digit.
- The problem states that the ones digit is less than 7, so it can be any digit from 0 to 6.
Step 2: Determine the possible values for the tens digit.
- The problem states that the value of the tens digit is 50. However, this is likely a typographical mistake, as a tens digit cannot be 50. Let's assume it is stating that the tens digit is greater than 5, but less than 10.
- Therefore, the tens digit can be 6, 7, 8, or 9.
Step 3: Combine the possible values for the ones and tens digits.
- We can combine each possible tens digit with each possible ones digit to find all the possible numbers.
- For the tens digit of 6: the possible ones digits are 0, 1, 2, 3, 4, 5, and 6. So, the possible numbers are 60, 61, 62, 63, 64, 65, and 66.
- For the tens digit of 7: the possible ones digits are 0, 1, 2, 3, 4, 5, and 6. So, the possible numbers are 70, 71, 72, 73, 74, 75, and 76.
- For the tens digit of 8: the possible ones digits are 0, 1, 2, 3, 4, 5, and 6. So, the possible numbers are 80, 81, 82, 83, 84, 85, and 86.
- For the tens digit of 9: the possible ones digits are 0, 1, 2, 3, 4, 5, and 6. So, the possible numbers are 90, 91, 92, 93, 94, 95, and 96.
Therefore, the possible numbers that satisfy the given conditions are 60, 61, 62, 63, 64, 65, 66, 70, 71, 72, 73, 74, 75, 76, 80, 81, 82, 83, 84, 85, 86, 90, 91, 92, 93, 94, 95, and 96.