write the dissociation of acetic acid identifying the base,acid,H donor, and H receiver
C2H4O2+H2O - H3O+C2H3O2
is hydronium the H donor and is C2H3O2 the base?
water is the base(H+ acceptor) and C2H4O2 is the acid(H+ donor) so Hydronium is the conjugate acid and C2H3O2 is the Conjugate base.
In the dissociation of acetic acid (C2H4O2) in water, the acid (H donor) is acetic acid, and the base (H receiver) is water. The dissociation reaction can be represented as follows:
C2H4O2 + H2O ⇌ H3O+ + C2H3O2-
In this reaction, acetic acid donates a hydrogen ion (H+) to a water molecule, forming hydronium ion (H3O+), while the acetate ion (C2H3O2-) is the conjugate base. Therefore, hydronium (H3O+) acts as the H donor, and C2H3O2- acts as the base.
In the given dissociation of acetic acid (C2H4O2) in water (H2O), the acid donates a proton (H+) to water molecules, which forms the hydronium ion (H3O+), while the acetate ion (C2H3O2-) acts as the base by accepting the proton.
To identify the acid, base, H donor, and H receiver in this reaction, we can break down the dissociation as follows:
Acid: Acetic acid (C2H4O2)
Base: Acetate ion (C2H3O2-)
H donor: Acetic acid (C2H4O2) donates a proton (H+) to water to form hydronium (H3O+)
H receiver: Water (H2O) accepts the proton from acetic acid to form hydronium (H3O+)
So, in summary, hydronium (H3O+) is the H donor, and the acetate ion (C2H3O2-) is the base in the dissociation of acetic acid.