Let f(x) be the function 6x^2-2x+8. Then the quotient (f(10+h)-f(10))/h can be simplified to ah+b for a and b eaquals what?

To simplify the quotient (f(10+h) - f(10))/h, we need to evaluate f(10+h) and f(10), and then simplify the expression.

First, let's evaluate f(10+h):

f(x) = 6x^2 - 2x + 8
f(10+h) = 6(10+h)^2 - 2(10+h) + 8
= 6(100 + 20h + h^2) - 20 - 2h + 8
= 600 + 120h + 6h^2 - 20 - 2h + 8
= 6h^2 + 118h + 588

Now, let's evaluate f(10):

f(x) = 6x^2 - 2x + 8
f(10) = 6(10)^2 - 2(10) + 8
= 6(100) - 20 + 8
= 600 - 20 + 8
= 588

Now we can substitute these values into the expression [(f(10+h) - f(10))/h]:

[(f(10+h) - f(10))/h] = [(6h^2 + 118h + 588 - 588)/h]
= (6h^2 + 118h)/h
= 6h + 118

Therefore, the quotient (f(10+h) - f(10))/h simplifies to the expression 6h + 118.