Condense the expression: 1/5log3(32) - 2log3x + 1/2log3y
I can't put the 3 as a small number on the bottom on all 3 parts of the trinomial.
I have a hunch you mean:
(1/5)log3(32) - 2log3(x) + (1/2)log3(y )
log 3(2) - log3(x^2) + log3(y^.5)
log3(2 x^-2 sqrt y )
Why.would.it.be.2x^e?
I have no idea where you got .2 x^e from.
0.2(X+3)-4(2x-3)=0.9
To condense the expression: 1/5log3(32) - 2log3x + 1/2log3y, we can use logarithmic properties to combine the terms into a single logarithm.
First, let's simplify each term using the power property of logarithms:
1/5log3(32) = log3(32)^(1/5) = log3(2^5) = log3(32)
2log3x = log3(x^2)
1/2log3y = log3(y^(1/2))
Now, we can combine the terms as follows:
log3(32) - log3(x^2) + log3(y^(1/2))
Using the quotient property of logarithms, we can rewrite the expression as a single logarithm:
log3(32/(x^2)) + log3(y^(1/2))
Now, let's simplify the expression further:
log3(32/(x^2) * y^(1/2))
Finally, we can further condense the expression:
log3(32y^(1/2)/x^2)
So, the condensed form of the expression is log3(32y^(1/2)/x^2).