# college algebra

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suppose you invest \$15,000 in two funds paying 11 1/2%and 14% simple interest. the total annual interest is \$1950. how much is invested in each fund?

• college algebra -

Amt. Invested in fund A = \$X.
Amt. invested in fund B = \$(15,000-X).

Int. = Prt.
t = 1yr.

x*0.115*1 + (15000-x)*0.14*1 = \$1950.
0.115x + 2100 - 0.14x = 1950,
-.025x = 1950 - 2100 = -150,
X = \$6,000.
15000 - X = 15000 - 6000 = \$9000.

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