trig
posted by Anonymous .
Write the expression and evaluate. There should only be one answer which should match the range of the inverse trig function.
Sec^1(2)
sec^1(sqrt2)
Cos^1((sqrt3)/2)
Tan^1(sqrt3)
Could someone explain how to get the answer as well please.

trig 
Henry
To limit the results to only one answer, the range must be limited to a
value between 0 and 180 degrees:
0 < A < 180.
secA = 1/cosA = 2,
cosA = 1/2,
A = 120 deg.
secA = 1/cosA = sqrt2,
cosA = 1/sqrt2,
A = 135 deg.
cosA = (sqrt3)/2,
A = 150 deg.
tanA = sqrt3,
A = 60 deg.,CW = 60 + 180 = 120 deg.
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