Two tugboats are towing a ship. each exerts a horizontal force of 5 tons and the angle between their tow ropes is 90. what net force is exerted on the ship?
To find the net force exerted on the ship, we need to calculate the horizontal components of the forces applied by each of the tugboats and add them together.
Given:
Force exerted by each tugboat = 5 tons
Angle between tow ropes = 90 degrees
Step 1: Calculate the horizontal component of each force.
Since the angle between the tow ropes is 90 degrees, the horizontal component of each force is the same as the magnitude of the force.
Horizontal component of the force exerted by each tugboat = 5 tons
Step 2: Add the horizontal components of the forces.
Since the tugboats are exerting forces in the same direction horizontally, we add the two forces together.
Net force exerted on the ship = Horizontal component of force exerted by the first tugboat + Horizontal component of force exerted by the second tugboat.
Net force exerted on the ship = 5 tons + 5 tons
Adding the forces together, we get:
Net force exerted on the ship = 10 tons
Therefore, the net force exerted on the ship is 10 tons.
To find the net force exerted on the ship, we need to calculate the vector sum of the forces exerted by the two tugboats.
Since the forces are acting at an angle, we can use vector addition to find the net force. In this case, the angle between the tow ropes is 90°, which means they are perpendicular to each other.
Now, let's break down the forces into their x and y components. Since the forces are horizontal, we can assume that the x direction is along the line of tugboats' motion, and the y direction is perpendicular to it.
Each tugboat exerts a horizontal force of 5 tons, so each force can be broken down as follows:
For the horizontal (x) component:
Force x = 5 tons * cos(90°) = 0
For the vertical (y) component:
Force y = 5 tons * sin(90°) = 5 tons
Since the x component is zero for both tugboats, we only need to consider the y component to find the net force.
Now, let's add the y components of the forces:
Net force y = Force y1 + Force y2 = 5 tons + 5 tons = 10 tons
Therefore, the net force exerted on the ship is 10 tons in the vertical (upward) direction.
29 tons
each is pulling in the forward direction 5cos45
so the net force =10cos45