Math OPTIMIZATION
posted by Willoby .
A home gardener plans to enclose two rectangular gardens with fencing. The dimensions of the garden: x by 12x, y by 12xy
a. Find the values of x and y that maximize the total area enclosed.
b. What is the maximum total area enclosed?
c. How many meters of fencing are needed?

The total area A=A(x,y).
A=x(12x)+y(12xy)=12xx^2+12yxyy^2
Partial derivatives
A'x=122xy
A'y=12x2y
Solve the equations A'x=A'y=0 => a. x=y=4
b. Amax=32+16=48
c. 24+16=40 
hey thanks! but where did you get 16 in b?

y(12xy)=4(1244)=16
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