Given a level of confidence of 99% and a population standard deviation of 7, answer the following:

(A) What other information is necessary to find the sample size (n)?
(B) Find the Maximum Error of Estimate (E) if n = 74. Show all work

(A) To find the sample size (n) with a given level of confidence and population standard deviation, we also need to know the desired margin of error (E) or the maximum acceptable difference between the sample mean and the population mean. The margin of error depends on the desired level of confidence and the variability in the population.

(B) To find the Maximum Error of Estimate (E) with a sample size (n) of 74, we can use the formula:

E = Z * (σ / sqrt(n))

Where:
- E is the maximum error of estimate
- Z is the Z-score corresponding to the desired level of confidence
- σ is the population standard deviation
- sqrt(n) is the square root of the sample size

For a 99% confidence level, the Z-score can be found from a Z-table or using a statistical calculator. The Z-score for a 99% confidence level is approximately 2.576.

Plugging in the values:
E = 2.576 * (7 / sqrt(74))

Calculating the square root:
E ≈ 2.576 * (7 / 8.602)

Simplifying the expression:
E ≈ 2.576 * 0.814

Calculating the multiplication:
E ≈ 2.100

Therefore, the Maximum Error of Estimate (E) with a sample size (n) of 74 is approximately 2.100.