If a swimmer has a lung volume of 6 at sea level, what would the volume of her lungs be when she is at the bottom of a pool that is 5 deep? Assume that the temperature and amount of the air in the lungs remain unchanged.

4L

6 WHAT and 5 WHAT. miles? mm?

6 Liters

To find the volume of a swimmer's lungs at the bottom of a pool, we need to consider the change in pressure as the swimmer goes from sea level to the bottom of the pool. The pressure in the atmosphere decreases as we descend, due to the weight of the air above us.

Here's how you can calculate the volume of the swimmer's lungs at the bottom of the pool:

1. Determine the change in pressure: The pressure at sea level is typically around 1 atmosphere (atm). For every 10 meters of water depth, the pressure increases by approximately 1 atm. In this case, the pool is 5 meters deep, so the pressure at the bottom of the pool will be 1 + (5/10) = 1.5 atm.

2. Apply Boyle's law: Boyle's law states that the pressure and volume of a gas are inversely proportional, assuming the temperature and amount of gas remain constant. Mathematically, it can be represented as P1*V1 = P2*V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Let's assume the initial lung volume (at sea level) is 6 (units are not specified, so we'll use a generic unit). We can set up the equation as follows:

1*6 = 1.5*V2

3. Solve for V2: Rearranging the equation, we have:

V2 = (1*6) / 1.5

V2 = 4

Therefore, the volume of the swimmer's lungs at the bottom of the pool would be 4 units, assuming the temperature and amount of air in the lungs remain constant.

It's important to note that this calculation assumes an ideal gas behavior and neglects effects such as dissolved gases in the bloodstream.