An irregular shaped stone was lowered intro a graduated cylinder holding a volume of water equal to 2.0 ml. The height of the water rose to 7.0 ml. If the mass of the stone was 25 g, what was the density
density = mass/volume.
mass = 25 g
volume = 7.0 - 2.0 = 5.0
5g/mL
To find the density of the irregular shaped stone, you can use the formula:
Density = Mass / Volume
Given:
Mass of the stone = 25 g
Initial volume of water = 2.0 ml
Final volume of water = 7.0 ml
Step 1: Calculate the change in volume:
Change in volume = Final volume - Initial volume
Change in volume = 7.0 ml - 2.0 ml
Change in volume = 5.0 ml
Step 2: Calculate the density:
Density = Mass / Change in volume
Density = 25 g / 5.0 ml
Since the units for density should be in g/ml, the density of the irregular shaped stone is 5 g/ml.
To calculate the density of the irregular-shaped stone, you need to use the formula:
Density = Mass / Volume
1. Start by determining the volume of the stone:
The initial volume of the water in the graduated cylinder is 2.0 mL, and the volume after the stone was added is 7.0 mL.
Therefore, the volume of the stone is equal to the final volume (7.0 mL) minus the initial volume (2.0 mL).
Volume of the stone = 7.0 mL - 2.0 mL = 5.0 mL (or 5.0 cm³)
2. Convert the volume of the stone to cubic centimeters (cm³):
Since 1 mL is equivalent to 1 cm³, the volume of the stone is already in cm³.
3. Now, you can calculate the density of the stone:
Density = Mass / Volume
Density = 25 g / 5.0 cm³ = 5 g/cm³
Therefore, the density of the irregular-shaped stone is 5 g/cm³.