A plane is sitting on a runway, awaiting takeoff. On an adjacent parallel runway, another plane lands and passes the stationary plane at a speed of 47 m/s. The arriving plane has a length of 32 m. By looking out the window (very narrow), a passenger on the stationary plane can see the moving plane. For how long a time is the moving plane visible?
How long does it take to go 32 meters at 47 m/s?
32 = 47 t
t = 32/47
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To determine the time for which the moving plane is visible to the passenger, we need to calculate the relative velocity between the two planes and divide the length of the arriving plane by this relative velocity. Let's break down the process step by step:
1. Calculate the relative velocity (v_rel) of the arriving plane with respect to the stationary plane. Since the arriving plane is landing and passing the stationary plane, the relative velocity is the sum of the landing speed (v_landing) of the arriving plane and the speed of the stationary plane (which is zero).
v_rel = v_landing + 0
v_rel = 47 m/s + 0
v_rel = 47 m/s
2. Calculate the time (t) the moving plane is visible by dividing the length of the moving plane (L_arriving) by the relative velocity.
t = L_arriving / v_rel
t = 32 m / 47 m/s
t = 0.68 seconds (approximately)
Therefore, the moving plane will be visible to the passenger for approximately 0.68 seconds.