algebra
posted by babygirl .
solve and check.label ant contradictions or identities.
5(t+1)+8=3(t2)+6
5t+5+8=3t6+6
5t+13=3t
2t=13
t=13/2
check59t+1)+8=3(t2)+6
5(13/2)+1+8=3(13/2)2)+6
65/2+13=39/2
13=39/2+65/2
13=26/2
13=13
want to know if this right

your solution is correct
in the check, most educators would expect you to work on each side independently and use
LS = .....
RS = .....
ending up with LS = RS
so you would have
LS = 5(13/2)+1+8
= 65/2+5 + 8
=  32.5 + 13
= 19.5
RS = 3(13/2)2)+6
= 39/2 6 + 6
= 39/2
=  19.5
= LS
so t = 13/2
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