A ball moving in a vertical circle of radius 0.8 meters has a speed of 4 m/s at the top. To the nearest tenth what is its acceleration at the top?

To find the acceleration at the top of the vertical circle, we can use the centripetal acceleration formula.

The centripetal acceleration (a) of an object moving in a circle is given by the formula:

a = (v^2) / r

Where:
a = centripetal acceleration
v = velocity
r = radius of the circle

In this case, the velocity (v) is given as 4 m/s and the radius (r) is given as 0.8 meters. Plugging these values into the formula, we get:

a = (4^2) / 0.8

Simplifying, we have:

a = 16 / 0.8

a = 20 m/s^2

Therefore, the acceleration at the top of the vertical circle is approximately 20 m/s^2 (to the nearest tenth).