Math
posted by Adriana
A man runs to a telephone and back in 15 minutes. His speed on the way to telephone is 15 m/s and his speed on the way back is 4m/s. Find the distance to the telephone.

Reiny
let the time one way be t seconds, then the time the other way has to be 900t seconds. (15 x 60 seconds = 900 seconds)
distance one way = 15t
distance the other way = 4(900t)
same distance either way, so
15t = 4(900t)
19t = 3600
t = 3600/19
distance = 15(3600/19) m or 2842.1 m or appr 2.84 km
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