algebra
posted by babygirl .
use the distributive law to factor the following and check 3+27b+6c

Remember when using the distributive law to factor you are in fact using factoring backwards.
Write each of your terms with the common multiplyer. Do you see the connection between all the numbers?
What number in the equation is the base for the rest. 3,right?
So write each term with 3 as you would as 27 and 6 as the answer.
Then you have 3(9b+2c)+3
When you check multiply each term in the parentheses and add three.
3x9b=27b
3x2c=6c
+3
Does that make sense?
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