The molecular mass of glucose is 180g/mol. you prepare a stock solution of glucose, by dissolving 1.8g of glucose in water to a final volume of 1.0L. The stock solution was then diluted as follows:
a. 50mL of the stock solution is added to 450mL of water,
b. and then 1.0mL of the diluted solution is added to 99mL of water. what is the μM concentration of the final solution?
Well, let's break it down step by step!
a. So we start with 50mL of the stock solution, which has a concentration of 1.8g/L. To dilute it, we add 450mL of water.
Now, we need to find the concentration after dilution. Using the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume, we can calculate the final concentration.
Let's plug in the values:
C1 = 1.8g/L
V1 = 50mL = 0.05L
C2 = ?
V2 = V1 + 450mL = 0.05L + 0.45L = 0.5L
Using the formula, we have:
C1V1 = C2V2
(1.8g/L)(0.05L) = C2(0.5L)
0.09g = 0.5C2
C2 = 0.09g/0.5L
C2 = 0.18g/L
b. Now, we take 1.0mL of the diluted solution, which has a concentration of 0.18g/L, and add it to 99mL of water.
Once again, using the same formula:
C1 = 0.18g/L
V1 = 1.0mL = 0.001L
C2 = ?
V2 = V1 + 99mL = 0.001L + 0.099L = 0.1L
Applying the formula:
C1V1 = C2V2
(0.18g/L)(0.001L) = C2(0.1L)
0.00018g = 0.1C2
C2 = 0.00018g/0.1L
C2 = 0.0018g/L
But wait, we need the concentration in μM (micromolar) instead of g/L.
To convert from g/L to μM, we need to multiply by the molar mass. The molar mass of glucose is 180g/mol.
C2 in μM = (0.0018g/L)(1000μM/1mM)(1mM/180g/mol)
C2 in μM = 0.01μM
So, the final concentration of the solution after all the dilutions is 0.01μM.
Hope that wasn't too diluted with information!
To calculate the μM (micromolar) concentration of the final solution, we need to follow these steps:
Step 1: Calculate the number of moles of glucose in the stock solution.
To do this, divide the mass of glucose (1.8g) by its molar mass (180g/mol):
1.8g / 180g/mol = 0.01 mol
Step 2: Calculate the concentration of the stock solution.
The stock solution has a volume of 1.0L (1000mL), so the concentration is given by:
Concentration = moles of solute / volume of solution
Concentration = 0.01 mol / 1.0 L = 0.01 M (molar)
Step 3: Calculate the concentration after the first dilution.
In this step, 50mL of the stock solution is added to 450mL of water. Add these volumes to get the total volume:
Total volume = 50mL + 450mL = 500mL = 0.5L
To calculate the concentration after the dilution, divide the number of moles by the new volume:
Concentration = moles of solute / volume of solution
Concentration = 0.01 mol / 0.5 L = 0.02 M
Step 4: Calculate the concentration after the second dilution.
In this step, 1.0mL of the diluted solution is added to 99mL of water. Add these volumes to get the total volume:
Total volume = 1.0mL + 99mL = 100mL = 0.1L
To calculate the concentration after the dilution, divide the number of moles by the new volume:
Concentration = moles of solute / volume of solution
Concentration = 0.02 mol / 0.1 L = 0.2 M
Step 5: Convert the concentration to micromolar (μM) units.
To convert from molar to micromolar, multiply by 1,000,000:
Concentration in μM = Concentration in M x 1,000,000
Concentration in μM = 0.2 M x 1,000,000 = 200,000 μM
Therefore, the μM concentration of the final solution is 200,000 μM.
To determine the μM concentration of the final solution, we need to calculate the number of moles of glucose in the final solution and then convert it to μM.
Let's break down the problem step by step:
1. Calculate the number of moles of glucose in the stock solution:
The molecular mass of glucose is given as 180g/mol. The mass of glucose dissolved in the stock solution is 1.8g. We can calculate the number of moles using the formula:
Moles = Mass / Molecular mass
Moles of glucose = 1.8g / 180g/mol = 0.01 mol
2. Calculate the number of moles of glucose in the first dilution:
In the first dilution, 50mL of the stock solution is added to 450mL of water. Therefore, the total volume of the solution after dilution is 50mL + 450mL = 500mL = 0.5L.
We can use the dilution formula to determine the number of moles of glucose in the diluted solution:
Moles of glucose in diluted solution = Moles of glucose in stock solution * (Volume of stock solution / Total volume after dilution)
Moles of glucose in diluted solution = 0.01mol * (50mL / 500mL) = 0.001mol
3. Calculate the number of moles of glucose in the second dilution:
In the second dilution, 1.0mL of the diluted solution is added to 99mL of water. The total volume of the solution after the second dilution is 1.0mL + 99mL = 100mL = 0.1L.
Applying the dilution formula again, we can calculate the number of moles of glucose in the final solution:
Moles of glucose in final solution = Moles of glucose in diluted solution * (Volume of diluted solution / Total volume after dilution)
Moles of glucose in final solution = 0.001mol * (1.0mL / 100mL) = 0.00001mol
4. Convert moles to micromoles (μmol):
To convert moles to micromoles, we multiply the number of moles by 1000000 (since 1 mole = 1,000,000 μmol):
μmol of glucose in final solution = Moles of glucose in final solution * 1000000
μmol of glucose in final solution = 0.00001mol * 1000000 = 10μmol
Therefore, the μM concentration of the final solution is 10μM.
1.8 g glucose/180 = 0.01 mole.
So 0.01 mole/L is the stock soln.
a. 0.01M x (50 mL/500 mL) = ?M
b. ?M x (1.0 mL/100 mL) = x M or x*1000 uM.
Technically, one cannot calculate values for a or b because volumes are not additive; however, since the concn is so low the difference is small enough it can be neglected. The correct way of doing this is
a. Add 50 mL of the stock solution to a 500 mL volumetric flack and add water for a final volume of 500 mL.
b. Add 1 mL of the solution from a to a 100 mL volumetric flask and make to a final volume of 100 mL.
b.