Hector rain in the city charity race for four years. His times in minutes were: 14.8, 22.3 , 26.7, and 31.9 . What was his average time for the four years to the nearest tenth of a minute?
14.8 + 22.3 + 26.7 + 31.9 = ?
Divide the sum by 4 to find the average.
The answer to this problem is 24 because
14.8+22.3+26.7+31.9=23.925 and 23.925 to the nearest tenth is 24.
To find the average time for the four years, you need to add up all the times and divide by the number of years.
Let's add up the four times Hector ran:
14.8 + 22.3 + 26.7 + 31.9 = 95.7
Now, divide the sum (95.7) by the number of years (4):
95.7 / 4 = 23.925
To round to the nearest tenth of a minute, we look at the digit in the hundredth place, which is 2. Since it is less than 5, we round down.
Therefore, Hector's average time for the four years is approximately 23.9 minutes.