Precalculus
posted by Jason
find any intercepts of the graph of the given equation. determine whether the graph of the equation possesses symmetry with respect to the xaxis, yaxis, or orgin
y=x^22x2

drwls
y = (x1)^2 3
When y = 0, (x1)^2 = 3
x  1 = + or  sqrt3
x = 1 + sqrt3 or 1  sqrt3
When x = 0, y = 3
There is no symmetry about the x or y axes, or origin. 
Damon
When x = 0, y = 2, y axis intercept
When y = 0
x = [ 2 +/ sqrt(4+8)]/2 = 1 +/ sqrt 3
therefore parabola is symmetric about the vertical line x = 1
show it by completing the square
x^2  2x = y + 2
x^2  2x + 1 = y+3
(x1)^2 = (y+3)
vertex at (1,3) 
Jason
thank you damon! that was exactly what i was looking for, by the way it's 4:32 am here and i've been searching for that answer for hours...
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