posted by jenny .
Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the symmetry of the graphs of sin, cos and tan, to find the exact values of si -pi/6, cos 5/3pi and tan 4pi/3.
I have found the answers to the first three using the special tables
sin(ƒÎ/6) = cos(ƒÎ/3) = 1/2
cos(ƒÎ/6) = sin(ƒÎ/3) = ã3/2
tan(ƒÎ/3) = ã3
tan(ƒÎ/6) = 1/ã3
I know that the symmetry of sin(-pi/6 is in the third quadrant, so 7pi/6 =
the symmetry of cos 5pi/3 i have taken 2pi - 5pi/3 to give cos pi/3 = 0.5 but i am not too sure where the symmetry comes in
With the tan I do not quite know where to start. Maybe pi + pi/3.
As for plotting the graphs of sin,cos and tan; I do not know where to start here using the pi radians (whereas as usually I am good at plotting graphs. (perhaps it is an age thing :-(
Your symbols baffle me. Sorry.
You have been using alt-251 for square-root, which probably works for Microsoft Word, but not for this forum which requires HTML codes.
For π, type in
& p i ;
(without the spaces in-between) and for
& r a d i c ;