A jogger runs in a straight line with an average velocity of v1=10.2 m/s for t1=6.0 min, and then with an average velocity of v2=7.7 m/s for t2=3.0 min. What is her total displacement? Answer in units of m.

v1*t1 + v2*t2

Make sure your t's are in seconds and your v's in m/s

To calculate the total displacement, you need to find the distance covered in each leg of the jog and then sum them up.

First, let's find the distance covered in the first leg of the jog.

Distance (d1) = Velocity (v1) x Time (t1)

Plugging in the values:

d1 = 10.2 m/s x (6.0 min x 60 s/min) = 10.2 m/s x 360 s = 3672 m

Next, let's find the distance covered in the second leg of the jog.

Distance (d2) = Velocity (v2) x Time (t2)

Plugging in the values:

d2 = 7.7 m/s x (3.0 min x 60 s/min) = 7.7 m/s x 180 s = 1386 m

Now, let's calculate the total displacement by adding the distances from both legs.

Total displacement = d1 + d2

Total displacement = 3672 m + 1386 m = 5058 m

Therefore, the total displacement of the jogger is 5058 m.