The velocity v of a roller coaster in feet per second at the bottom of a hill is Where h is the height of the hill in feet.
Simplify the equation.
Determine the velocity of a roller coaster at the bottom of a 134-foot hill.
I think I just answered the same question, but somehow the posting has disappeared.
the equation in that post was
v = √(64h)
so when h = 134
v = √(64*134) = √ 8576 = appr. 92.6
Reiny,
So the velocity at the bottom of a 134-foot hill would be v= 92.607?
*Making a litle more sense to me now. Thank you for your input.
To simplify the equation, we need to substitute the given height value in the equation and calculate the velocity.
The equation for the velocity v of a roller coaster at the bottom of a hill, given the height h, is:
v = √(32h)
Substituting the given height h = 134 feet into the equation, we get:
v = √(32 * 134)
Calculating this expression:
v ≈ √(4288)
v ≈ 65.5
Therefore, the velocity of the roller coaster at the bottom of a 134-foot hill is approximately 65.5 feet per second.
To simplify the equation, we need to understand the given information. The equation for the velocity of a roller coaster at the bottom of a hill is given as:
v = sqrt(2gh)
where v is the velocity in feet per second, g is the acceleration due to gravity (approximately 32.2 feet per second squared), and h is the height of the hill in feet.
Now let's determine the velocity of a roller coaster at the bottom of a 134-foot hill using the given equation.
Substituting the value of h = 134 into the equation, we have:
v = sqrt(2 * 32.2 * 134)
Calculating further:
v = sqrt(8617.6)
v ≈ 92.92 feet per second (rounded to two decimal places)
Therefore, the velocity of the roller coaster at the bottom of a 134-foot hill is approximately 92.92 feet per second.