If a charge of 25 coulombs passes a given point in circuit in a time of 125 minutes determine the current in the circuit
t = 125min * 60s/min = 7500s.
I = Q/t = 25/7500 = 0.00333 Amperes.
To determine the current in the circuit, we can use the equation:
current (I) = charge (Q) / time (t)
Given:
Charge (Q) = 25 coulombs
Time (t) = 125 minutes
However, in order to calculate the current correctly, we need to convert the time from minutes to seconds, as the SI unit of time is seconds.
To convert minutes to seconds, we know that there are 60 seconds in a minute. Therefore, we can multiply the given time by 60:
Time (t) = 125 minutes * 60 seconds/minute = 7500 seconds
Now we can substitute the values into the equation:
current (I) = 25 coulombs / 7500 seconds
Calculating this, we find:
current (I) = 0.00333 Amperes (or 3.33 milliamperes)
Therefore, the current in the circuit is approximately 0.00333 Amperes.