physics

posted by .

1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?

(Note: this question refers to Newton’s equation for the force of gravity between two objects. How would that change if the radius of the earth or distance were increased by 100,000 meters. To help you answer this question, please review your textbook, chapter 3, Newton’s law of Gravitation section.)

  • physics -

    the force diminishes by the square of distance.


    acceleration due to gravity= 9.8 (r/re)^2

    re radius of earth
    r is distance from center of Earth.

  • physics -

    so what is the answer

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    How far above the surface of the Earth does an object have to be in order for it to have the same weight as it would have on the surface of the Moon?
  2. science

    The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?
  3. science

    The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?
  4. Physics

    The value of acceleration due to gravity (g) on a point 10,000 kilometers above sea level is about 1.49 meters/second2. How much will an object, which weighs 98 newtons on the surface of Earth, weigh on this point?
  5. Physics

    The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?
  6. Physics THRUST

    To begin I just need to know how to do thrust. A lunar lander in powered descent at 100 m above the surface of the moon slows down from a velocity of 20 m/s to 0.5 m/s at constant acceleration. Assume that the lander has a mass of …
  7. physics

    1. The acceleration due to gravity calculated this way works well for objects near the Earth’s surface. How would you have to change the above equation if the object was 100,000 meters above the ground?
  8. Grade 12 Physics

    A rocket ship is moving away from the earth after having been fired from a launch pad in Florida. At what point above the earth's surface will the force of gravity be reduced to ½ of its original value?
  9. Physics

    At 6400 km above the earth’s surface, an object weighing 71 N on the surface would weigh only 18 N. Acceleration due to gravity will be about ¼ that on the surface of the earth.
  10. IPC

    The value of acceleration due to gravity (g) on a point 10,000 kilometers above sea level is about 1.49 meters/second2. How much will an object, which weighs 98 newtons on the surface of Earth, weigh on this point?

More Similar Questions