MATH
posted by Sowmya Sri .
X+Y=5XY,3X+2Y=13XY where x and y are not equl to 0

3(X+Y=5XY)
3X+2Y=13XY
3X+3Y=15XY (1)
3X+2Y=13XY (2)

SUBTRACT (1)(2)
Y=2XY
CANCEL Y ON BOTH SIDES
=> 2X=1
=>X=1/2
FROM EQUATION (1)
3Y=15XY3X
3Y=3(5XYX)
CANCEL 3
Y=5XYX
=>5XYY=X
=>Y(5X1)=X (3)
NOW SUBSTITUTE X IN EQUATION (3)
Y(5*(1/2)1)=1/2
=>Y[(5/2)1]=1/2
=>Y[2.51]=0.5
=>Y[1.5]=0.5
=>Y[3]=1
=>Y=1/3
THEREFORE X=1/2 & Y=1/3
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