Identify the graph of the equation. What is the angle of rotation for the equation?
y^2+8x=0
How do i figure this out? I think it has to be a hyperbola.
http://www.freemathhelp.com/equation-grapher.html
enter as y = (-8*x)^.5
Note that it will not graph for positive x because the square root of a negative number is imaginary.
To identify the graph of the equation and determine the angle of rotation, we need to rewrite the given equation in a standard form for conic sections.
The equation provided is y^2 + 8x = 0.
To determine the graph, we can rearrange the equation to isolate y^2.
y^2 = -8x
Now, let's analyze the equation.
Since y^2 is dependent on x, we can deduce that this equation represents a sideways-opening parabola. The parabola is centered on the y-axis because there is no term involving y, and the coefficient of x is positive.
Regarding the angle of rotation, the equation does not indicate any rotation. Therefore, the angle of rotation is 0 degrees.
In conclusion, the graph of the equation y^2 + 8x = 0 is a sideways-opening parabola centered on the y-axis, with no rotation.