Student A gets 40%maxmium marks and 10 above pass mark.Student B gets 50%maxmium marks and 50 above pass mark.find the pass mark.
To find the pass mark, we need to analyze the information given for both Student A and Student B.
We know that Student A gets 40% of the maximum marks and is 10 marks above the pass mark. Let's assume the maximum marks are represented by 'M', and the pass mark is represented by 'P'.
From this information, we can write the equation: 40% of M = P + 10.
Similarly, we know that Student B gets 50% of the maximum marks and is 50 marks above the pass mark. Using the same variables, we can write the equation: 50% of M = P + 50.
To find the pass mark, we need to solve these two equations simultaneously.
Let's solve the first equation: 0.40M = P + 10.
Now, let's solve the second equation: 0.50M = P + 50.
To eliminate the variable 'P', we can subtract the first equation from the second:
(0.50M - 0.40M) = (P + 50) - (P + 10).
This simplifies to: 0.10M = 40.
To find the value of 'M', we can divide both sides by 0.10:
0.10M / 0.10 = 40 / 0.10.
This gives us: M = 400.
Now, we can substitute the value of 'M' back into either of the original equations to find the pass mark. Let's use the first equation:
0.40(400) = P + 10.
This simplifies to: 160 = P + 10.
To find the value of 'P', we subtract 10 from both sides:
P = 160 - 10.
Therefore, the pass mark is 150.
So, the pass mark is 150 marks.