# Precalc

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How would I put this parabola in standard form: x^2-6x+8y-31

Here how I started it:

x^2-6x+9=-8y+31

Im not sure what to do from here :(

• Precalc -

If x^2-6x+8y-31 mean:

x^2-6x+8y-31=0 then

8y= -x^2+6x+31 Divide with 8

y= -x^2/8 + 6x/8 + 31/8

y= -x^2/8 + 3x/4 + 31/8

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