Precalc
posted by Cinderella .
How would I put this parabola in standard form: x^26x+8y31
Here how I started it:
x^26x+9=8y+31
Im not sure what to do from here :(

If x^26x+8y31 mean:
x^26x+8y31=0 then
8y= x^2+6x+31 Divide with 8
y= x^2/8 + 6x/8 + 31/8
y= x^2/8 + 3x/4 + 31/8