A rubber ball weighs 49 N. What is the acceleration of the ball if an upward force of 69 N is

applied?

4 meters / (seconds squared)

Hint: The net force on the ball is

F = 69 - 49 = 20 N

The mass of the ball is
M = 49/g = 5.0 kg

The acceleration is a = F/M

Well, if a rubber ball weighs 49 N and you apply an upward force of 69 N, it's safe to say that the ball will probably start flying to the moon! Remember kids, safety first! But on a serious note, the acceleration can be calculated using Newton's second law: F = ma, where F is the net force, m is the mass, and a is the acceleration. So if you rearrange the equation, you get a = F/m. Plugging in the values, a = 69 N / 49 N ≈ 1.41 m/s². So, the acceleration of the ball would be approximately 1.41 m/s². Just remember to hold on tight to that rubber ball, unless you want to go on an unexpected space adventure!

To find the acceleration of the ball, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied on it and inversely proportional to its mass. The formula for Newton's second law is:

F = ma

Where F is the net force, m is the mass of the object, and a is the acceleration.

In this case, the upward force of 69 N is the applied force on the ball, and we need to find the acceleration. We know that the weight of the ball is 49 N, which is its downward force. Since weight is the force due to gravity, it is equal to the mass of the object multiplied by the acceleration due to gravity (9.8 m/s^2 on Earth).

Weight = mg

Given that weight = 49 N and g = 9.8 m/s^2, we can rearrange the formula to find the mass:

m = weight / g

m = 49 N / 9.8 m/s^2
m = 5 kg

Now we have the mass of the ball (m = 5 kg) and the net force (F = 69 N). Plugging these values into Newton's second law, we can solve for the acceleration:

F = ma

69 N = 5 kg * a

To isolate the acceleration, divide both sides by 5 kg:

69 N / 5 kg = a

a = 13.8 m/s^2

Therefore, the acceleration of the ball when an upward force of 69 N is applied is 13.8 m/s^2.

13.8