Calculus :)

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find y'(x) if x^y=y^x

  • Calculus :) -

    x^y=y^x --->

    y log(x) = x log(y) ----->

    log(x) dy + y/x dx =
    log(y) dx + x/y dy ---->

    [log(x) - x/y] dy = [log(y) - y/x] dx

    ---->

    dy/dx = [log(y) - y/x]/[log(x) - x/y]

  • Calculus :) -

    Go on :

    wolframalpha dot com

    When page be open in rectangle type:

    derivative x^y=y^x

    and click option =

    When you see result click option:

    Show steps

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