A farmer has both chickens and sheep on his farm. He has a total of 25 animals and there are 72 legs on his farm. How many of each animal is there?
(I think the answer is 18 (sheep) as chickens are birds not animals!!!
a bird is a type of animal, you idiot.
A farmer has both chickens and sheep on his farm. He has a total of 25 animals and there are 72 legs on his farm. How many of each animal is there?
25(animals)*2(legs)=50 legs, we tack just two legs for both.
72-50=22
22/2=11 sheep’s
25-11=14 chickens
Check:
11*4=44
14*2=28
44+28=72
not the correct answers
hi
A farmer owns a total of 25 chickens and horses.
The chickens and horses have 88 legs altogether.
How many horses are there?
A farmer owns a total of 28 ducks and cows.
The ducks and cows have 98 legs altogether.
How many cows are there?
A farmer owns a total of 26 chickens and donkeys.
The chickens and donkeys have 88 legs altogether.
How many donkeys are there?
To solve this problem, we can use a system of equations. Let's assume that the number of chickens is represented by 'C' and the number of sheep is represented by 'S.'
We know that the total number of animals is 25. So, we can write the equation:
C + S = 25
We also know that the total number of legs on the farm is 72. Chickens have 2 legs, and sheep have 4 legs. So, we can write the equation:
2C + 4S = 72
To solve these equations, we can use the method of substitution. Rearranging the first equation to solve for C, we get:
C = 25 - S
Substituting this value of C into the second equation, we get:
2(25 - S) + 4S = 72
50 - 2S + 4S = 72
50 + 2S = 72
2S = 22
S = 11
Now that we have the value of S, we can substitute it back into the first equation to find the value of C:
C + 11 = 25
C = 25 - 11
C = 14
Therefore, there are 14 chickens and 11 sheep on the farm.
c = chickens
s = sheep
c+s = 25
2 c + 4 s = 72 or c + 2 s = 36
from first equation c = 25-s
so
25 - s + 2 s = 36
s = 11
then c = 14