Algebra2

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Can someone EXPLAIN to me how to solve for x. Please don't just give me an answer because I won't learn anything from that.

sq root of (x+6) = x

  • Algebra2 -

    (x+6)^.5 = x


    multiply both sides by (x+6)^.5

    (x+6) = x(x+6)^.5 but (x+6)^.5 is x
    so
    x+6 = x^2
    x^2 - x - 6 = 0

    (x-3)(x+2) - 0
    so x = 3 or x=-2
    try x = 3
    sqrt(9) = 3 sure enough
    try x = -2
    sqrt (4) = -2 nope, negative root does not check
    so x = 3 is the answer.

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