# Algebra2

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Can someone EXPLAIN to me how to solve for x. Please don't just give me an answer because I won't learn anything from that.

sq root of (x+6) = x

• Algebra2 -

(x+6)^.5 = x

multiply both sides by (x+6)^.5

(x+6) = x(x+6)^.5 but (x+6)^.5 is x
so
x+6 = x^2
x^2 - x - 6 = 0

(x-3)(x+2) - 0
so x = 3 or x=-2
try x = 3
sqrt(9) = 3 sure enough
try x = -2
sqrt (4) = -2 nope, negative root does not check
so x = 3 is the answer.

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