Algebra2
posted by Juan .
Can someone EXPLAIN to me how to solve for x. Please don't just give me an answer because I won't learn anything from that.
sq root of (x+6) = x

(x+6)^.5 = x
multiply both sides by (x+6)^.5
(x+6) = x(x+6)^.5 but (x+6)^.5 is x
so
x+6 = x^2
x^2  x  6 = 0
(x3)(x+2)  0
so x = 3 or x=2
try x = 3
sqrt(9) = 3 sure enough
try x = 2
sqrt (4) = 2 nope, negative root does not check
so x = 3 is the answer.
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