a bowling ball has a diameter of 8.4 in. It is made of plastic that weighs 0.05lb/in cubed.Find the weight of the bowling ball
volume of sphere = (4/3) pi r^3
so
V = (4/3) pi (4.2)^3
weight = .05 * V
Its actually very easy
You do
V= 4(3.14)(4.2^3) Divide by 3
Then do volume * 0.05
The answer would be
V = 15.5lb
Yes, that is correct! The weight of the bowling ball is 15.5 pounds.
To find the weight of the bowling ball, we need to calculate its volume first and then multiply it by the weight per cubic inch of plastic.
The volume of a sphere can be calculated using the formula:
V = (4/3) * π * r^3
Where:
V = Volume
π = Pi (approximately 3.14)
r = radius of the sphere (half of the diameter)
Given that the diameter of the bowling ball is 8.4 inches, we can find the radius by dividing the diameter by 2:
r = 8.4 / 2 = 4.2 inches
Now let's calculate the volume:
V = (4/3) * 3.14 * (4.2^3)
V ≈ 4.18879 * 74.088
V ≈ 309.276 cubic inches
Next, we multiply the volume by the weight per cubic inch of plastic:
Weight = V * Weight per cubic inch
Given that the weight per cubic inch is 0.05 lb/in^3,
Weight = 309.276 * 0.05
Weight ≈ 15.464 lb
Therefore, the weight of the bowling ball is approximately 15.464 pounds.