Trig/precalc
posted by A
r=8cos(theta)+5sin(theta), convert the polar equation into a rectangular equation and then complete the square and determine the center radius...?
Help?! I missed the section, and am not getting anywhere with the text...

Reiny
In your text, you should find a diagram similar to this one
http://en.wikipedia.org/wiki/File:Polar_to_cartesian.svg
If you label the endpoint of the rotating arm as either
(x,y) in rectangular and (r,Ø) in polar, then
x = rcosØ or cosØ = x/r
y = rsinØ or sinØ = y/r
also x^2 + y^2 = r^2, and tanØ = y/x
then in your equation r = 8(x/r) + 5(y/r)
multiply by r
r^2 = 8x + 5y
x^2 + y^2 = 8x + 5y
x^2  8x + y^2  5y = 0
This is the equation of a circle. I will assume you know how to complete the square and thus find the centre and radius.
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