posted by Joordan
A proton is fired with a speed of 3.00 X 10^6 m/s directly towards a large and positively charged plane of surface charge density +9.25 X 10^-7 C/m^2 . If the proton starts 1m from the plane, the minimum distance between the proton and the plane is closest to.. ?
A) 0cm B) 10cm C) 45cm D) 55cm E) 90cm
I know the answer is B, but not quite sure why :S
Any help would be appreciated, thank you.
Use the surface charge density to compute the E field perpendicular to the plate. The field will be independent of distance from the plate, if the plate is large compared to the distance from the plate.
E = (charge density)/(epsilon-zero)
Minimum distance occurs when the work done by the proton against the field the field equals the initial kinetic energy.
Be sure to subtract the distabnce travelled from 1 meter to get the distance from the wall at turnaround.