Post a New Question

Physics

posted by .

A 40 g marble moving at 2.3 m/s strikes a 29 g marble at rest. Assume the collision is perfectly elastic and the marbles collide head-on. What is the speed of the first marble immediately after the collision? What is the speed of the second marble immediately after the collision?

How do you set this up?

  • Physics -

    two equations: Conservation of momentum
    M1V1+m2(0)=M1V1' + m2V2'
    solve for v2' in terms of all others.
    second equation: conservation of energy
    M1V1^2+0=M1V1'^2 + m2V2'^2
    put the v2' equation into that equation, and solve for v1'

    A bit of algebra is required, get a pad of paper.

  • Dont get it? -

    I tried plugging the number in and it didn't work...where are the numbers supposed to be placed in the first equation?

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question