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A manufacturer constructs open boxes from sheets of cardboard that are 6 inches square by cutting small squares from the corners and folding up the sides. The Research and Development Department asks you to determine the size of the square that produces a box of greatest volume. Proceed as follows. Let x be the length of a side of the square to be cut and V be the volume of the resulting box. Show that V = x(6-2x)^2. I don't understand how I'm suppose to show what they are asking.

  • Calculus -

    make a sketch of a 6 by 6 square.
    Draw squares at each corner of x by x
    (You could actually cut them out with scissors)
    This would allow you to fold up the sides to form a box
    Wouldn't each side of the base remaining be 6 - 2x, since x units were taken away at each end ?
    Wouldn't the height of the box be x ?

    volume = base x height
    = (6-2x)(6-2x(x)
    = x(6-2x)^2

  • Calculus -

    I just wasn't sure if the answer was simply a sketch, 6 - 2x each side with the cut-outs. Thanks!!

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