trig
posted by Anonymous .
If z=1+i, then the multiplicative inverse of z esqaire is:

trig 
drwls
What does z esqaire mean?
According to Wikipedia,
"In mathematics, a multiplicative inverse or reciprocal for a number x, denoted by 1/x or x^−1, is a number which when multiplied by x yields the multiplicative identity, 1."
Accordingly, the multiplicative inverse of 1 + i is
1/(1+i) = (1i)/[1i)(1+i)]
= (1i)/2
If you want the multiplicative inverse of z^2, where z = 1+i,
that would be 1/z^2 = 1/(1+i)^2
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