A tennis ball is held stationary and then dropped from the roof of a tall building. What will be its velocity after 3.0 s?
V = -g*t, where
g = 9.8 m/s^2 (on Earth)
The minus sign is because the acceleration is in the negatve direction, assuming + is up.
V(t=3s)= -29.4 m/s
Air resistance has been neglected. That will slow it down.
To find the velocity of the tennis ball after 3.0 seconds, we need to consider the acceleration due to gravity.
The acceleration due to gravity is approximately 9.8 m/s^2, which means that every second an object falls, its velocity increases by 9.8 m/s.
To find the velocity of the tennis ball after 3.0 seconds, we can use the equation:
velocity = initial velocity + acceleration * time
Since the tennis ball is dropped from rest, its initial velocity is 0 m/s. Plugging in the values, we get:
velocity = 0 m/s + 9.8 m/s^2 * 3.0 s = 29.4 m/s
Therefore, the velocity of the tennis ball after 3.0 seconds is 29.4 m/s.