Physical Chemistry
posted by Alfred .
1.6 mol of Neon gas are heated from 20.0 °C to 85.2 °C at a constant pressure of 1 atm. Calculate
the work done. (R = 0.082057 L.atm/ K. mol)

Work done = (Pressure)*(Volume change)
= P(nR(T2T1)]/P
= n*R(T2T1)
= 1.6(0.082057 L.atm/ K. mol)*65.2K
= 8.56 L*atm
Those are inconvenient units for work, so multiply by 10^3 m^2/L*(1.013*10^5 N/m^2/atm
I get 867 Nm (Joules) 
so the formula is W = nR∆T
Thank you for the answer above:) 
W=nRT
=(1.6)(O.O82507)(65)
=8.53J
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