Login or Sign Up

Ask a New Question

When using the student's t distribution to test mu, what value do you use for the degrees of freedom if the sample size is 42?

a. 41
b. Can not be determined from information given.
c. 43
d. 42

by definition, 42-1 or 41 degrees of freedom

Similar Questions

On a test whose distribution is approximately normal with a mean of 50 and a standard deviation of 10, the results for three

Top answer: T = 50 + 10Z Z = your score in terms of standard deviations. With this information, you should be Read more.
On a test whose distribution is approximately normal with a mean of 50 and a standard deviation of 10, the results for three

Top answer: Since the Z and T score are standard for any normal distribution, you don't even need to know the Read more.
The average (arithmetic mean) of a normal distribution of a school's test scores is 65, and standard deviation of the

Top answer: Her score is 2 standard deviations above the mean. Only 2.3% are higher. Call it the 97th percentile Read more.
A college student takes a standardized test and scores a 163. If the mean is 155 and the standard deviation is 7, what is the

Top answer: Z = (score-mean)/SD Find table in the back of your statistics text labeled something like "areas Read more.
A college student takes a standardized test and scores a 163. If the mean is 155 and the standard deviation is 7, what is the

Top answer: Well, let's clown around with some statistics! To find the student's percentile rank, we need to Read more.
Assume that a test is given to a large number of people but we do not yet know their scores or the shape of the score

Top answer: Answered in a later post. Read more.
Assume that a test is given to a large number of people but we do not yet know their scores or the shape of the score

Top answer: The larger the sample size, the more you can safely approximate the normal distribution. Read more.
A test given to a class of students revealed that most did quite well, and only a few did very poorly. How would you describe

Top answer: It seems like your distribution is negatively skewed (skewed left, with the tail pointing to the Read more.
a test consists of true/false questions .to pass the test a student must answer at least 6questions correctly .if a student

Top answer: .377 Read more.
. The average time a student spends studying just prior to a test is 36 minutes with a standard deviation of 7 minutes. This

Top answer: To find the percent of students who study just prior to the test for more than 60 minutes, we need Read more.