chemistry

posted by J.T

What mass of PbCl2 would be found in 0.48 L of a saturated solution of PbCl2 if the Ksp of PbCl2 is 1.6 x 10-5?

1. Drbob222

..........PbCl2(s) ==> Pb^2+ + 2Cl^-
x = solubility..x.......x.......2x
Ksp = (Pb^2+)(Cl^-)^2
Ksp = (x)(2x)^2
Solve for x which will give you the moles/L of PbCl2.
Mols/L x 0.48 L = moles in 480 mL.
Then moles x molar mass PbCl2 = grams PbCl2.

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