When Pal throws his beach ball straight up in the air, it's height h at time tis given by h=(-1/2)gt^2+v(sub 0). Find the velocity of the ball when t=0.
To find the velocity of the ball when t=0, we need to use the given equation h=(-1/2)gt^2+v₀ and substitute t=0.
Let's plug in t=0 into the equation:
h = (-1/2)g(0)^2 + v₀
h = 0 + v₀
h = v₀
So, when t=0, the height of the ball is equal to the initial velocity v₀.
Therefore, the velocity of the ball when t=0 is v₀.