3x+4y=12 how to find the slope and y-intercept
4 y = - 3 x + 12
y = -(3/4) x + 3
slope = -3/4
y axis intercept is when x = 0
y = 0 + 3 so 3
thanks Damon.
To find the slope and y-intercept of the equation 3x + 4y = 12, you can use the standard form of a linear equation, which is y = mx + b. In this form, 'm' represents the slope and 'b' represents the y-intercept.
To rewrite the given equation in the standard form, you need to isolate 'y' on one side of the equation:
3x + 4y = 12
4y = -3x + 12 (Subtract 3x from both sides)
y = (-3/4)x + 3 (Divide both sides by 4)
Now that the equation is in the standard form, you can easily identify the slope and y-intercept:
The slope, 'm', is the coefficient of 'x', which in this case is -3/4.
So, the slope of the equation 3x + 4y = 12 is -3/4.
The y-intercept, 'b', is the constant term in the equation, which is 3.
So, the y-intercept of the equation 3x + 4y = 12 is 3.
Therefore, the slope is -3/4 and the y-intercept is 3.