if the coefficient of kinetic friction between a 35-kg crate and the floor is 0.30, what horizontal force is required to move the crate at a steady speed across the floor? what horizontal force is required uk is zero?
For horizontal surfaces,and constant speed,
M*g*uk = F
uk is the kinetic friction coefficient.
Both questions can be answered using that formula. Try it.
In your second question (last sentence), you omitted the word "if" after "required". Be more careful copying your questions.
To find the horizontal force required to move the crate at a steady speed across the floor, we can use the equation:
F = μk * N
where F is the force required, μk is the coefficient of kinetic friction, and N is the normal force.
1. Find the normal force (N):
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the weight of the crate.
N = m * g
where m is the mass of the crate and g is the acceleration due to gravity (approximately 9.8 m/s^2).
N = 35 kg * 9.8 m/s^2
2. Calculate the force required (F):
F = μk * N
F = 0.30 * (35 kg * 9.8 m/s^2)
Now, let's calculate the force required.
F = 0.30 * (35 kg * 9.8 m/s^2)
F = 0.30 * 343 N
F = 102.9 N
Therefore, the horizontal force required to move the crate at a steady speed across the floor is approximately 102.9 Newtons.
Now, let's consider the case where the coefficient of kinetic friction (μk) is zero.
If the coefficient of kinetic friction is zero (μk = 0), it means there is no friction between the crate and the floor. In this case, no horizontal force is required to move the crate at a steady speed, as there is no opposition to the motion. The crate will continue to move with a constant velocity once it is set in motion.